(3x+1)(2+2x)-6x^2=1+8x

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Solution for (3x+1)(2+2x)-6x^2=1+8x equation: 


Simplifying
(3x + 1)(2 + 2x) + -6x2 = 1 + 8x

Reorder the terms:
(1 + 3x)(2 + 2x) + -6x2 = 1 + 8x

Multiply (1 + 3x) * (2 + 2x)
(1(2 + 2x) + 3x * (2 + 2x)) + -6x2 = 1 + 8x
((2 * 1 + 2x * 1) + 3x * (2 + 2x)) + -6x2 = 1 + 8x
((2 + 2x) + 3x * (2 + 2x)) + -6x2 = 1 + 8x
(2 + 2x + (2 * 3x + 2x * 3x)) + -6x2 = 1 + 8x
(2 + 2x + (6x + 6x2)) + -6x2 = 1 + 8x

Combine like terms: 2x + 6x = 8x
(2 + 8x + 6x2) + -6x2 = 1 + 8x

Combine like terms: 6x2 + -6x2 = 0
2 + 8x + 0 = 1 + 8x
2 + 8x = 1 + 8x

Add '-8x' to each side of the equation.
2 + 8x + -8x = 1 + 8x + -8x

Combine like terms: 8x + -8x = 0
2 + 0 = 1 + 8x + -8x
2 = 1 + 8x + -8x

Combine like terms: 8x + -8x = 0
2 = 1 + 0
2 = 1

Solving
2 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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